Question

evaluate algebraic expressions
given the formula for the area of a trapezoid: ( a = \frac { h } { 2 } ( b _ { 1 } + b _ { 2 } ) )
find the area of a trapezoid where:
height, ( h = 6 ) units
base one, ( b _ { 1 } = 3 ) units
base two, ( b _ { 2 } = 7 ) units
( a = ) square units

Explanation:

Step1: Substitute the values into the formula

Given \(A=\frac{h}{2}(b_1 + b_2)\), \(h = 6\), \(b_1=3\), \(b_2 = 7\). Substitute these values: \(A=\frac{6}{2}(3 + 7)\)

Step2: Simplify the expression inside the parentheses

First, calculate \(3+7\): \(3 + 7=10\). So the formula becomes \(A=\frac{6}{2}\times10\)

Step3: Simplify the fraction

\(\frac{6}{2}=3\). Now the formula is \(A = 3\times10\)

Step4: Multiply

\(3\times10 = 30\)

Answer:

\(30\)