Question

the equation of a linear function in point-slope form is $y - y_1 = m(x - x_1)$. harold correctly wrote the equation $y = 3(x - 7)$ using a point and the slope. which point did harold use?
○ $(7, 3)$
○ $(0, 7)$
○ $(7, 0)$
○ $(3, 7)$

Explanation:

Step1: Recall Point - Slope Formula

The point - slope form of a linear equation is \(y - y_1=m(x - x_1)\), where \((x_1,y_1)\) is a point on the line and \(m\) is the slope.

Step2: Analyze the Given Equation

The given equation is \(y = 3(x - 7)\). We can rewrite it in the form \(y-0=3(x - 7)\) (by subtracting 0 from \(y\)). Comparing this with the point - slope form \(y - y_1=m(x - x_1)\), we can see that \(y_1 = 0\) and \(x_1=7\). So the point \((x_1,y_1)\) is \((7,0)\).

Answer:

C. \((7, 0)\)