Question

elise, jake, malik, and xiao each solved the same inequality.

elises work	jakes work	maliks work	xiaos work

whose work is correct?
\\(\bigcirc\\) elises work

Explanation:

Step1: Isolate absolute value term

Start with the original inequality:
$$|6x| + 3 \leq 0$$
Subtract 3 from both sides:
$$|6x| \leq -3$$

Step2: Analyze absolute value property

By definition, the absolute value of any real number $|a| \geq 0$ for all real $a$. There is no real number whose absolute value is less than or equal to a negative number.

Answer:

Malik's work