Question

the edge of a flying disc with a radius of 0.13 m spins with a tangential speed of 3.3 m/s. the centripetal acceleration of the edge of the disc is \boxed{} \text{m/s}^2

Explanation:

Step1: Recall the formula for centripetal acceleration

The formula for centripetal acceleration \( a_c \) is \( a_c=\frac{v^2}{r} \), where \( v \) is the tangential speed and \( r \) is the radius.

Step2: Substitute the given values into the formula

We are given that \( v = 3.3\space m/s \) and \( r = 0.13\space m \). Substituting these values into the formula, we get \( a_c=\frac{(3.3)^2}{0.13} \).

Step3: Calculate the numerator

First, calculate \( (3.3)^2 \). \( 3.3\times3.3 = 10.89 \).

Step4: Divide the numerator by the denominator

Now, divide \( 10.89 \) by \( 0.13 \). \( \frac{10.89}{0.13}\approx83.27 \).

Answer:

83.27 (approximate value, depending on calculation precision)