Question

due nov 9 11:59pm available from nov 3 until nov 9
discussion 6: find area
find the area of the trapezoid in the figure. explain and show work. simplify the answer.
hint: since this graph doesnt claim its drawn to - scale, one should assume its not - scale. inspect carefully to verify first that there is no right angle in this trapezoid.
use the insert math equation tool (√3 icon) to typeset math equations and expressions.
reply

Explanation:

Step1: Simplify the side lengths

Simplify \(2\sqrt{63}\), \(2\sqrt{27}\)

• \(2\sqrt{63}=2\sqrt{9\times7}=2\times3\sqrt{7}=6\sqrt{7}\)
• \(2\sqrt{27}=2\sqrt{9\times3}=2\times3\sqrt{3}=6\sqrt{3}\)

Step2: Use the trapezoid area formula \(A = \frac{(a + b)h}{2}\)

Here \(a = 6\sqrt{7}\), \(b = 7\sqrt{7}\), \(h = 6\sqrt{3}\)

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Answer:

\(39\sqrt{21}\text{ m}^2\)