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a discrete random variable x can assume five possible values, 23, 24, 2…

Question

a discrete random variable x can assume five possible values, 23, 24, 25, 26, and 27. the following histogram shows the likelihood of each value. complete parts a through c below. a. what is p(27)? p(27) = 0.35 (type an integer or a decimal. do not round.) b. what is the probability that x equals 24 or 26? p(24 or 26) = \square (type an integer or a decimal. do not round.)

Explanation:

Step1: Identify p(24) and p(26)

From the histogram, p(24) is 0.05 (the bar for 24) and p(26) is 0.25 (the bar for 26).

Step2: Apply addition rule for mutually exclusive events

For mutually exclusive events (x can't be 24 and 26 at the same time), \( P(24 \text{ or } 26) = p(24) + p(26) \).
Substitute the values: \( 0.05 + 0.25 = 0.3 \).

Answer:

0.3