Question

in the diagram, which must be true for point p to be the centroid of the triangle?
○ ln ⊥ jk, jo ⊥ lk, and jl ⊥ mk.
○ jl = lk = kj
○ jm = ml, lo = ok, and kn = nj.
○ ln is a perpendicular bisector of jk, jo is a perpendicular bisector of lk, and mk is a perpendicular bisector of jl.

Explanation:

Step1: Recall centroid definition

The centroid of a triangle is the point of intersection of the medians of the triangle. A median of a triangle is a line - segment that joins a vertex to the mid - point of the opposite side.

Step2: Analyze each option

• Option 1: $\overline{LN}\perp\overline{JK},\overline{JO}\perp\overline{LK},\overline{JL}\perp\overline{MK}$ represents perpendiculars, not medians.
• Option 2: $JL = LK=KJ$ means the triangle is equilateral, which has nothing to do with the centroid property.
• Option 3: $JM = ML, LO = OK, KN = NJ$ implies that $M, O, N$ are mid - points of $\overline{JL},\overline{LK},\overline{KJ}$ respectively. So, $\overline{JN},\overline{LO},\overline{KM}$ are medians and their intersection point $P$ is the centroid.
• Option 4: $\overline{LN}$ being a perpendicular bisector of $\overline{JK}$, etc. represents perpendicular bisectors, not medians.

Answer:

$JM = ML, LO = OK, and\ KN = NJ$