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Question
the diagram shows a triangle. 30° 6b 4b what is the value of b? b = ° submit
Step1: Use the triangle angle sum theorem
The sum of angles in a triangle is \(180^{\circ}\). So, \(30^{\circ}+6b + 4b=180^{\circ}\).
Step2: Combine like terms
Combine \(6b\) and \(4b\). We get \(30^{\circ}+10b = 180^{\circ}\).
Step3: Solve for \(b\)
Subtract \(30^{\circ}\) from both sides: \(10b=180^{\circ}- 30^{\circ}=150^{\circ}\). Then divide both sides by \(10\), \(b=\frac{150^{\circ}}{10}=15^{\circ}\).
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