QUESTION IMAGE
Question
in the diagram, dg = 15, gf = 5, eh = 12, and de = 8. to prove that △dfe ~ △gfh by the sss similarity theorem using the information provided in the diagram, it would be enough additional information to know that
○ hf is 2 units and gh is 3 units.
○ hf is 3 units and gh is 2 units.
○ hf is 4 units and gh is 2 units.
○ hf is 3 units and gh is 4 units.
Step1: Recall SSS Similarity
For \(\triangle DFE \sim \triangle GFH\) by SSS, \(\frac{DF}{GF}=\frac{FE}{FH}=\frac{DE}{GH}\). First, find \(DF = DG + GF = 15 + 5 = 20\), \(FE = EH + HF = 12 + HF\).
Step2: Check Ratios
We know \(DE = 8\), \(GF = 5\), \(DF = 20\). So \(\frac{DF}{GF}=\frac{20}{5}=4\), \(\frac{DE}{GH}=\frac{8}{GH}\), \(\frac{FE}{FH}=\frac{12 + HF}{FH}\). For similarity, \(\frac{8}{GH}=4\) (so \(GH = 2\)) and \(\frac{12 + HF}{FH}=4\) (simplify: \(12 + HF = 4FH \Rightarrow 12 = 3FH \Rightarrow FH = 4\)? Wait, no—wait, let's check each option. Wait, maybe I miscalculated. Wait, \(DF = DG + GF = 15 + 5 = 20\), \(GF = 5\), so ratio \(DF/GF = 20/5 = 4\). Then \(DE/GH\) should be 4, so \(8/GH = 4 \Rightarrow GH = 2\). Then \(FE = EH + HF = 12 + HF\), and \(FE/FH\) should be 4, so \((12 + HF)/FH = 4 \Rightarrow 12 + HF = 4FH \Rightarrow 12 = 3FH \Rightarrow FH = 4\)? Wait, no, the options: let's check each option.
Wait, maybe I messed up. Let's re-express. The sides of \(\triangle DFE\) are \(DF = 20\), \(DE = 8\), \(FE = 12 + HF\). The sides of \(\triangle GFH\) are \(GF = 5\), \(GH\), \(FH\). For SSS similarity, the ratios of corresponding sides must be equal. So \(\frac{DF}{GF}=\frac{DE}{GH}=\frac{FE}{FH}\).
\(\frac{DF}{GF}=\frac{20}{5}=4\). So \(\frac{DE}{GH}=4 \Rightarrow \frac{8}{GH}=4 \Rightarrow GH = 2\). Then \(\frac{FE}{FH}=4 \Rightarrow \frac{12 + HF}{FH}=4 \Rightarrow 12 + HF = 4FH \Rightarrow 12 = 3FH \Rightarrow FH = 4\)? But the options: let's check the options. Wait, the options are:
- HF=2, GH=3: \(\frac{8}{3}
eq4\), no.
- HF=3, GH=2: \(\frac{8}{2}=4\), good. Then \(FE = 12 + 3 = 15\), \(FH = 3\), \(\frac{15}{3}=5\)? Wait, no, that's not 4. Wait, I must have mixed up the sides. Wait, maybe the correspondence is \(\triangle DFE \sim \triangle GFH\), so \(DF\) corresponds to \(GF\), \(FE\) corresponds to \(FH\), \(DE\) corresponds to \(GH\). Wait, no, maybe the order is different. Wait, \(D\) corresponds to \(G\), \(F\) corresponds to \(F\), \(E\) corresponds to \(H\). So sides: \(DF\) (D to F), \(GF\) (G to F); \(FE\) (F to E), \(FH\) (F to H); \(DE\) (D to E), \(GH\) (G to H). So \(DF = 20\), \(GF = 5\); \(FE = 12 + HF\), \(FH = HF\); \(DE = 8\), \(GH = GH\). So ratios: \(DF/GF = 20/5 = 4\), \(DE/GH = 8/GH\), \(FE/FH = (12 + HF)/HF\). For similarity, all ratios must be 4. So \(8/GH = 4 \Rightarrow GH = 2\), and \((12 + HF)/HF = 4 \Rightarrow 12 + HF = 4HF \Rightarrow 12 = 3HF \Rightarrow HF = 4\). But the options: wait, the fourth option is HF=3, GH=4: \(\frac{8}{4}=2
eq4\). Wait, maybe I got the correspondence wrong. Maybe \(\triangle DFE \sim \triangle GFH\) with \(D\) to \(G\), \(E\) to \(F\), \(F\) to \(H\)? No, that doesn't make sense. Wait, let's look at the diagram: \(DE\) and \(GH\) are both vertical (assuming), \(EH\) and \(HF\) are horizontal, \(DF\) and \(GF\) are the hypotenuses. So \(\triangle DFE\) has legs \(DE = 8\), \(FE = 12 + HF\), hypotenuse \(DF = 20\). \(\triangle GFH\) has legs \(GH\), \(FH\), hypotenuse \(GF = 5\). So for similarity, the ratio of legs should be equal to ratio of hypotenuses. So \(\frac{DE}{GH}=\frac{FE}{FH}=\frac{DF}{GF}\). \(DF/GF = 20/5 = 4\). So \(\frac{DE}{GH}=4 \Rightarrow GH = 8/4 = 2\). \(\frac{FE}{FH}=4 \Rightarrow (12 + FH)/FH = 4 \Rightarrow 12 + FH = 4FH \Rightarrow 3FH = 12 \Rightarrow FH = 4\). Wait, but the options: the third option is HF=4, GH=2. Wait, the third option is "HF is 4 units and GH is 2 units"—wait, no, the options are:
- HF is 2 units and GH is 3 units.
- HF is 3 units and GH is 2 units.
- HF is 4 units and GH is 2 units.
- HF…
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The correct option is: HF is 4 units and GH is 2 units. (The third option)