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QUESTION IMAGE

describe how to graph the solution of \\(y \\le -x^2 + 2x\\).

Question

describe how to graph the solution of
\\(y \le -x^2 + 2x\\).

Explanation:

Identify the boundary curve and inequality type

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Determine key features of the parabola

$$ LATEXBLOCK1 $$

Determine the shaded region using a test point

$$ LATEXBLOCK2 $$

Answer:

To graph the solution of \(y \le -x^2 + 2x\):

  1. Graph the boundary parabola \(y = -x^2 + 2x\) as a solid line because the inequality includes "or equal to" (\(\le\)). The parabola opens downward with its vertex at \((1, 1)\) and x-intercepts at \((0, 0)\) and \((2, 0)\).
  2. Shade the region below (inside) the parabola. You can verify this by testing the point \((1, 0)\): since \(0 \le -(1)^2 + 2(1)\) is true (\(0 \le 1\)), shade the region containing this point.