Question

decide whether the following problem can be solved using precalculus or whether calculus is required. if the problem can be solved using precalculus solve it! if it cannot be solved using precalculus type dne
find the area of the shaded region bounded by the triangle with vertices $(-1,0),(4,5),(9,0)$
this problem requires select an answer \\( \bigcirc \\) to solve.

Explanation:

Step1: Find the base length

The base of the triangle is the distance between \((-1,0)\) and \((9,0)\). Using the distance formula \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\), since \(y_1 = y_2=0\), \(b=\vert9-(-1)\vert=10\).

Step2: Find the height

The height \(h\) is the \(y -\)coordinate of the vertex \((4,5)\), so \(h = 5\).

Step3: Calculate the area

The area formula for a triangle is \(A=\frac{1}{2}\times b\times h\). Substitute \(b = 10\) and \(h=5\) into the formula: \(A=\frac{1}{2}\times10\times5\).

Answer:

\(25\)