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darrell wants to see how much water is wasted by his leaky faucet. he p…

Question

darrell wants to see how much water is wasted by his leaky faucet. he puts a 4 - gallon bucket under the faucet. after 24 hours, the bucket is full. if the same amount of water leaks each hour, how much water will leak in 60 hours?

water (gallons)4

Explanation:

Step1: Find the leakage rate per hour

The faucet leaks 4 gallons in 24 hours. So the rate \( r \) is \( \frac{4}{24} \) gallons per hour. Simplify \( \frac{4}{24}=\frac{1}{6} \) gallons per hour.

Step2: Calculate water leakage in 60 hours

Using the rate, the amount of water \( W \) in 60 hours is \( r\times60 \). Substitute \( r = \frac{1}{6} \), so \( W=\frac{1}{6}\times60 = 10 \) gallons. Alternatively, set up a proportion: \( \frac{4}{24}=\frac{x}{60} \), cross - multiply: \( 24x = 4\times60 \), \( 24x=240 \), then \( x = \frac{240}{24}=10 \).

Answer:

10 gallons