QUESTION IMAGE
Question
darrell wants to see how much water is wasted by his leaky faucet. he puts a 4 - gallon bucket under the faucet. after 24 hours, the bucket is full. if the same amount of water leaks each hour, how much water will leak in 60 hours?
| water (gallons) | 4 |
|---|
Step1: Find the leakage rate per hour
The faucet leaks 4 gallons in 24 hours. So the rate \( r \) is \( \frac{4}{24} \) gallons per hour. Simplify \( \frac{4}{24}=\frac{1}{6} \) gallons per hour.
Step2: Calculate water leakage in 60 hours
Using the rate, the amount of water \( W \) in 60 hours is \( r\times60 \). Substitute \( r = \frac{1}{6} \), so \( W=\frac{1}{6}\times60 = 10 \) gallons. Alternatively, set up a proportion: \( \frac{4}{24}=\frac{x}{60} \), cross - multiply: \( 24x = 4\times60 \), \( 24x=240 \), then \( x = \frac{240}{24}=10 \).
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10 gallons