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Question
cosa = \frac{b^{2}+c^{2}-a^{2}}{2bc}
(sss)
Step1: Identify the sides for the cosine formula
Let \(a = 10\), \(b = 14\), \(c = 18\). The cosine formula is \(\cos A=\frac{b^{2}+c^{2}-a^{2}}{2bc}\).
Step2: Substitute the values into the formula
$$
LATEXBLOCK0
$$
Step3: Find the angle \(A\)
\(A=\cos^{-1}(\frac{5}{6})\approx33.56^{\circ}\)
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The measure of angle \(A\) is approximately \(33.56^{\circ}\)