Question

construct a frequency distribution table.

1. number of cars per household in a subdivision was recorded

4, 0, 1, 1, 0, 3, 2, 3, 2, 1, 1, 0, 1, 2, 2

1. heights of 15 basketball players in centimeters

165, 188, 175, 180, 183, 183, 188, 175,
183, 173, 193, 173, 175, 175, 180

Explanation:

19. Number of cars per household

Step1: List all unique values

The unique values of number of cars are \(0\), \(1\), \(2\), \(3\), \(4\).

Step2: Count the frequency of each value

• For \(0\): Count the number of \(0\)s in \(4,0,1,1,0,3,2,3,2,1,1,0,1,2,2\). There are \(3\) zeros.
• For \(1\): Count the number of \(1\)s. There are \(5\) ones.
• For \(2\): Count the number of \(2\)s. There are \(4\) twos.
• For \(3\): Count the number of \(3\)s. There are \(2\) threes.
• For \(4\): Count the number of \(4\)s. There is \(1\) four.

Step1: List all unique values

The unique values of heights are \(165\), \(173\), \(175\), \(180\), \(183\), \(188\), \(193\).

Step2: Count the frequency of each value

• For \(165\): Count the number of \(165\)s in \(165,188,175,180,183,183,188,175,183,173,193,173,175,175,180\). There is \(1\) \(165\).
• For \(173\): Count the number of \(173\)s. There are \(2\) \(173\)s.
• For \(175\): Count the number of \(175\)s. There are \(4\) \(175\)s.
• For \(180\): Count the number of \(180\)s. There are \(2\) \(180\)s.
• For \(183\): Count the number of \(183\)s. There are \(3\) \(183\)s.
• For \(188\): Count the number of \(188\)s. There are \(2\) \(188\)s.
• For \(193\): Count the number of \(193\)s. There is \(1\) \(193\).

Answer:

Number of Cars	Frequency
\(1\)	\(5\)
\(2\)	\(4\)
\(3\)	\(2\)
\(4\)	\(1\)

20. Heights of basketball players