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consider the line \\(4x + 8y = -9\\). find the equation of the line tha…

Question

consider the line \\(4x + 8y = -9\\).

find the equation of the line that is perpendicular to this line and passes through the point \\((-3, -6)\\).

find the equation of the line that is parallel to this line and passes through the point \\((-3, -6)\\).

equation of perpendicular line:
equation of parallel line:

Explanation:

Find the slope of the given line

$$ LATEXBLOCK0 $$

Find the equation of the perpendicular line

$$ LATEXBLOCK1 $$

Find the equation of the parallel line

$$ LATEXBLOCK2 $$

Answer:

Consider the line \(4x + 8y = -9\).

Find the equation of the line that is perpendicular to this line and passes through the point \((-3, -6)\).
Equation of perpendicular line: <blank>\(y = 2x\)</blank>

Find the equation of the line that is parallel to this line and passes through the point \((-3, -6)\).
Equation of parallel line: <blank>\(y = -\frac{1}{2}x - \frac{15}{2}\)</blank>