Question

consider the following salaries for the executives of a certain company.
position\tsalary
president\t$190,000
1st vp\t$130,000
2nd vp\t$120,000
supervising manager\t$64,000
accounting manager\t$50,000
personnel manager\t$50,000
department manager\t$30,000
department manager\t$30,000
what is the mode? (enter your answers as a comma - separated list. if an answer does not exist, enter dne.)
30,000 × dollars
suggested tutorial: learn it find the mean, median, and mode of a data set

Explanation:

Step1: Recall the definition of mode

The mode is the value that appears most frequently in a data set.

Step2: Count the frequency of each salary

• \( \$190,000 \): 1 time
• \( \$130,000 \): 1 time
• \( \$120,000 \): 1 time
• \( \$64,000 \): 1 time
• \( \$50,000 \): 2 times (Accounting manager and Personnel manager)
• \( \$30,000 \): 2 times (Two Department managers)

Wait, wait, let's re - check. Wait, the salaries are: \( 190000, 130000, 120000, 64000, 50000, 50000, 30000, 30000 \)

So \( \$50,000 \) appears 2 times, \( \$30,000 \) appears 2 times. Wait, but wait, maybe I made a mistake earlier. Wait, no, let's count again:

• \( 190000 \): frequency 1
• \( 130000 \): frequency 1
• \( 120000 \): frequency 1
• \( 64000 \): frequency 1
• \( 50000 \): frequency 2 (Accounting manager and Personnel manager)
• \( 30000 \): frequency 2 (two Department managers)

Wait, but actually, when we look at the data:

The salaries are: \( 190000, 130000, 120000, 64000, 50000, 50000, 30000, 30000 \)

So both \( 30000 \) and \( 50000 \) have a frequency of 2, which is the highest frequency (since all others have frequency 1). Wait, the original answer was wrong because it only considered \( 30000 \), but \( 50000 \) also has the same frequency.

Wait, let's list the frequencies properly:

• \( 190000 \): 1
• \( 130000 \): 1
• \( 120000 \): 1
• \( 64000 \): 1
• \( 50000 \): 2
• \( 30000 \): 2

So the values with the highest frequency (2) are \( 30000 \) and \( 50000 \).

Answer:

30000, 50000