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Question
consider the distribution of the numbers of people whose street address ends in 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 (the data set has 10 values). complete parts (a) through (d) below
a. how many peaks would you expect for the distribution? explain
a. there would probably be two peaks, one close to the least number, 0, and one close to the greatest number, 9, because those are the numbers that everyone picks for their address
b. there would probably be one peak. many streets are long, and the addresses for people living on those streets are large numbers, so the peak would be at a number close to 9
c. there would probably be no peaks. when all street addresses are considered, the distribution of the last digit tends to be uniform
d. there would probably be many peaks corresponding to each of the last digits that are even numbers, because there are always more buildings on the even side of the street
To determine the number of peaks in the distribution of the last digits of street addresses, we analyze the nature of street address numbering. Street addresses are typically assigned in a sequential manner across various streets, and there's no inherent bias for a particular last digit (0 - 9) to be more common than others when considering all streets. A uniform distribution has no peaks because all values (last digits here) occur with approximately equal frequency. Option A is incorrect as there's no reason 0 and 9 would be preferentially chosen. Option B is incorrect as street addresses don't inherently cluster around 9. Option D is incorrect as there's no universal rule that even - numbered sides of streets always have more buildings, and even if they did, it wouldn't create peaks for each even digit in a way that's consistent across all streets. So the correct reasoning is that the distribution of the last digit of street addresses tends to be uniform, meaning no peaks.
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C. There would probably be no peaks. When all street addresses are considered, the distribution of the last digit tends to be uniform