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Question
complete the tasks to subtract the polynomials vertically. (1.3t^3 + 0.4t^2 - 24t)-(0.6t^2 + 8 - 18t) what is the additive inverse of the polynomial being subtracted? -0.6t^2+(-8)+(-18t) -0.6t^2+(-8)+18t -0.6t^2 + 8 - 18t 0.6t^2+(-8)+18t done
Step1: Recall additive inverse concept
The additive inverse of a polynomial \(a + b + c\) is \(-a - b - c\).
The polynomial being subtracted is \(0.6t^{2}+8 - 18t\).
Step2: Find the additive - inverse
Change the sign of each term. The additive inverse is \(-0.6t^{2}+(- 8)+18t\).
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\(-0.6t^{2}+(- 8)+18t\) (corresponding to the second option in the multiple - choice list)