QUESTION IMAGE
Question
complete this table, and determine the rule for this transformation.
type your answers in the boxes.
| input | output |
|---|---|
| (4, 5) | (5, 4) |
| (?, 4) | (4, 0) |
| (1, 5) | (?, ?) |
| (?, ?) | (-1, -2) |
| (x, y) | (?, ?) |
determine the rule for this transformation.
type your answer in the box.
(x, y) → (?, ?)
Step1: Analyze first pair
Input \((2, -3)\), Output \((-3, 2)\). Notice \(x = 2\) becomes \(y=-3\) (output \(x\)), \(y = -3\) becomes \(x = 2\) (output \(y\))? Wait, no: output \(x\) is original \(y\) (but sign? Wait \(2\) to \(-3\)? Wait no, wait \((2,-3)\) to \((-3,2)\): original \(x = 2\), output \(y = 2\); original \(y=-3\), output \(x=-3\). Wait, swap \(x\) and \(y\) and... Wait, no: \((x,y)\) to \((y, x)\)? Wait \((2,-3)\) would be \((-3,2)\) – yes! Because \(x=2\), \(y=-3\); swap to \((y,x)=(-3,2)\). Check next pair: \((4,5)\) to \((5,4)\)? Wait the output is \((5,4)\)? Wait the image shows output \((5,4)\) for input \((4,5)\). Yes! So \((4,5)\) swapped \(x\) and \(y\) gives \((5,4)\). Third pair: input \((?, 4)\) output \((4, 0)\). So if rule is \((x,y)\to(y,x)\), then input \(y = 4\) becomes output \(x = 4\), input \(x\) becomes output \(y = 0\). So input \(x\) must be \(0\), so input is \((0,4)\). Fourth pair: input \((1,5)\), apply rule \((y,x)=(5,1)\). Fifth pair: output \((-1,-7)\), so input is \((-7,-1)\) (since \((x,y)\to(y,x)\), so \(y=-1\), \(x=-7\) gives output \((-1,-7)\)). The rule is swapping \(x\) and \(y\) coordinates, so \((x,y)\to(y,x)\).
Step2: Verify with second pair
Input \((4,5)\), output \((5,4)\) – which is \((y,x)\) (since \(x=4\), \(y=5\); swap to \((5,4)\)). Correct. Third pair: input \((0,4)\) (since output \((4,0)\) is \((y,x)\) where \(y=4\), \(x=0\)). Fourth pair: input \((1,5)\) gives output \((5,1)\). Fifth pair: output \((-1,-7)\) means input is \((-7,-1)\) (since \((y,x)=(-1,-7)\) implies \(y=-1\), \(x=-7\)).
Step3: Determine the rule
From the pairs, the transformation rule is swapping the \(x\)- and \(y\)-coordinates, so \((x, y) \to (y, x)\).
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\((y, x)\)