Question

1. complete the steps to solve the equation.

\\(\frac{1}{5}t + 2 - \square = 17 - \square\\)
\\(\frac{1}{5}t = \square\\)
\\(\square \cdot \frac{1}{5}t = \square\\)
\\(t = \square\\)

Explanation:

Step1: Subtract 2 from both sides

To isolate the term with \( t \), we subtract 2 from both sides of the equation \( \frac{1}{5}t + 2 - \boxed{2} = 17 - \boxed{2} \).

Step2: Simplify both sides

After subtracting 2, we get \( \frac{1}{5}t = \boxed{15} \) (since \( 17 - 2 = 15 \)).

Step3: Multiply by 5 (reciprocal of \( \frac{1}{5} \))

To solve for \( t \), we multiply both sides by 5: \( \boxed{5} \cdot \frac{1}{5}t = \boxed{5} \cdot 15 \).

Step4: Simplify to find \( t \)

Simplifying the left side ( \( 5 \cdot \frac{1}{5}t = t \) ) and the right side ( \( 5 \cdot 15 = 75 \) ), we get \( t = \boxed{75} \).

Answer:

First two boxes: \( 2 \), \( 2 \); Third box: \( 15 \); Fourth box: \( 5 \); Fifth box: \( 75 \); Sixth box: \( 75 \) (Note: The steps show the filled values for each box in order. The final value of \( t \) is \( 75 \).)