QUESTION IMAGE
Question
$$\overline{xy}\cong\overline{vw},\angle s\cong\angle u$$, and $$\angle uxv\cong\angle swy$$. complete the proof that $$\triangle uvx\cong\triangle syw$$.
| statement | reason | |
|---|---|---|
| 2 | $$\angle s\cong\angle u$$ | given |
| 3 | $$\angle uxv\cong\angle swy$$ | given |
| 4 | $$wy = xy + wx$$ | additive property of length |
| 5 | $$vx = vw + wx$$ | additive property of length |
| 6 | $$wy = vw + wx$$ | substitution |
| 7 | $$vx = wy$$ | transitive property of equality |
| 8 | $$\triangle uvx\cong\triangle syw$$ |
Step1: Recall the AAS (Angle - Angle - Side) Congruence Theorem
The AAS congruence theorem states that if two angles and a non - included side of one triangle are congruent to two angles and the corresponding non - included side of another triangle, then the two triangles are congruent.
Step2: Identify the corresponding parts
We are given that \(\angle S\cong\angle U\) (one pair of angles), \(\angle UXV\cong\angle SWY\) (another pair of angles), and from step 7 we have \(VX = WY\) (a non - included side).
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By the AAS (Angle - Angle - Side) Congruence Theorem.