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complete the chart to find the mean, variance and standard deviation. r…

Question

complete the chart to find the mean, variance and standard deviation. remember to use commas and round numbers to the nearest tenth.

x(\bar{x})(x - \bar{x})((x - \bar{x})^2)
2. 340= - 87.5the variance is
3. 400= - 27.5the standard deviation is
4. 625= 197.5(n =)
(sum x=)(\bar{x}=)(sum(x - \bar{x})^2 = 54,225.0)

Explanation:

Step1: Calculate sum of \(X\) values

\(\sum X=345 + 340+400 + 625=1710\)

Step2: Calculate the mean \(\bar{X}\)

The number of data - points \(n = 4\). \(\bar{X}=\frac{\sum X}{n}=\frac{1710}{4}=427.5\)

Step3: Calculate \((x-\bar{X})^2\) for each \(x\) value

  • For \(x = 345\): \((x-\bar{X})^2=(- 82.5)^2 = 6806.25\)
  • For \(x = 340\): \((x-\bar{X})^2=(-87.5)^2=7656.25\)
  • For \(x = 400\): \((x-\bar{X})^2=(-27.5)^2 = 756.25\)
  • For \(x = 625\): \((x-\bar{X})^2=(197.5)^2=39006.25\)

Step4: Calculate the variance \(s^{2}\)

The variance \(s^{2}=\frac{\sum(x - \bar{X})^2}{n}=\frac{54225}{4}=13556.25\approx13556.3\)

Step5: Calculate the standard deviation \(s\)

The standard deviation \(s=\sqrt{s^{2}}=\sqrt{13556.25}\approx116.4\)

Answer:

\(\sum X = 1710\), \(\bar{X}=427.5\), for \(x = 345\), \((x - \bar{X})^2=6806.3\), for \(x = 340\), \((x - \bar{X})^2=7656.3\), for \(x = 400\), \((x - \bar{X})^2=756.3\), for \(x = 625\), \((x - \bar{X})^2=39006.3\), the variance is \(13556.3\), the standard deviation is \(116.4\), \(n = 4\)