Question

click the arrows to choose an answer from each menu.

the volume of ice in shape 1 is choose... cubic centimeters.

the volume of ice in shape 2 is choose... cubic centimeters.

shape 1 contains choose... ice as shape 2.

alicia choose... correct.

Explanation:

Step1: Volume of Shape 1 (Pyramid with rectangular base)

The formula for the volume of a pyramid is $V = \frac{1}{3}Bh$, where $B$ is the area of the base and $h$ is the height. For Shape 1, the base is a rectangle with length $4$ cm and width $3$ cm, so $B = 4 \times 3 = 12$ $cm^2$. The height $h$ is $5$ cm. Then $V_1 = \frac{1}{3} \times 12 \times 5$.
$V_1 = 4 \times 5 = 20$ $cm^3$.

Step2: Volume of Shape 2 (Pyramid with triangular base)

For Shape 2, the base is a triangle with base $4$ cm and height $3$ cm, so $B = \frac{1}{2} \times 4 \times 3 = 6$ $cm^2$. The height $h$ is $5$ cm. Then $V_2 = \frac{1}{3} \times 6 \times 5$.
$V_2 = 2 \times 5 = 10$ $cm^3$.

Step3: Comparison of Volumes

To find how much more ice Shape 1 has than Shape 2, we see $V_1 = 20$, $V_2 = 10$, so Shape 1 has twice as much ice as Shape 2 (since $20 = 2 \times 10$).

Answer:

The volume of ice in shape 1 is $\boldsymbol{20}$ cubic centimeters.
The volume of ice in shape 2 is $\boldsymbol{10}$ cubic centimeters.
Shape 1 contains $\boldsymbol{twice\ as\ much}$ ice as shape 2. (Assuming Alicia's part relates to this comparison, e.g., if she said Shape 1 has twice, she is correct.)