Question

the city of raleigh has 7900 registered voters. there are two candidates for city council in an upcoming election: brown and feliz. the day before the election, a telephone poll of 500 randomly selected registered voters was conducted. 289 said theyd vote for brown, 195 said theyd vote for feliz, and 16 were undecided.
give the sample statistic for the proportion of voters surveyed who said theyd vote for brown. note: the proportion should be a fraction or decimal, not a percent.

this sample statistic suggests that we might expect of the 7900 registered voters to vote for brown.
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Explanation:

Step1: Calculate the proportion of voters surveyed for Brown

The formula for proportion is \(p=\frac{\text{Number of favorable cases}}{\text{Total number of cases}}\). Here, the number of voters who said they'd vote for Brown is \(289\), and the total number of surveyed voters is \(500\). So, \(p = \frac{289}{500}=0.578\).

Step2: Estimate the number of voters for Brown in the whole population

We use the formula \(N = p\times\text{Total population}\). Given \(p = 0.578\) and the total number of registered voters \(7900\). Then \(N=0.578\times7900 = 4566.2\).

Answer:

0.578
4566.2