Question

a city election for a city council seat was held between 4 candidates, martorana (m), jervey (j), riddell (r), and hanrahan (h). the preference schedule for this election is below.
number of voters: 60, 73, 84, 25, 110
1st choice: m, m, h, j, j
2nd choice: r, h, r, r, m
3rd choice: h, r, m, m, r
4th choice: j, j, j, h, h
how many voters voted in the election?
options: 110, 352, 327, 452

Explanation:

Step1: Sum the number of voters

To find the total number of voters, we add up the number of voters in each column: \(60 + 73 + 84 + 25 + 110\).

Step2: Calculate the sum

First, \(60 + 73 = 133\). Then, \(133 + 84 = 217\). Next, \(217 + 25 = 242\). Finally, \(242 + 110 = 352\).

Answer:

352 (corresponding to the option "352")