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circle the most accurate answer for each item. each item only has one c…

Question

circle the most accurate answer for each item. each item only has one correct solution. if you choose more than one answer, the item will be marked incorrect.

  1. two companies offer jane a sales position. company a pays $3,000 each month plus $250 per car sold. company b pays $2,500 each month plus $350 per car sold. which equation could be used to determine the number of cars sold in a month, x, that would result in the same total income from each company?

a. 3,000x + 250 = 2,500x + 350
b. 3,000x - 250 = 2,500x - 350
c. 3,000 + 250x = 2,500 + 350x
d. 3,000 - 250x = 2,500 + 350x

  1. in the equation below, what values will result in no solution?

4x - 2(3x + 7) = __x - __
a. -4 and 7
b. -2 and 7
c. -2 and 14
d. 4 and 14

Explanation:

Step1: Analyze Company A's income

Company A pays a fixed amount of \( \$3000 \) per month and \( \$250 \) per car sold. If the number of cars sold is \( x \), then the total income from Company A is \( 3000 + 250x \).

Step2: Analyze Company B's income

Company B pays a fixed amount of \( \$2500 \) per month and \( \$350 \) per car sold. If the number of cars sold is \( x \), then the total income from Company B is \( 2500 + 350x \).

Step3: Set the two incomes equal

To find the number of cars \( x \) for which the total income is the same from both companies, we set the two expressions equal to each other: \( 3000 + 250x = 2500 + 350x \).

Answer:

C. \( 3,000 + 250x = 2,500 + 350x \)