Question

1. chris has a cone with a radius of 5 inches and a height of 12 inches. what is the approximate volume of the cone?

a. 377.00 in.³
b. 188.50 in.³
c. 942.48 in.³
d. 314.16 in.³

1. cody uses a battery shaped like a cylinder for his flashlight. the radius of the battery is 16.5 mm, and it has a volume of 15,908.5 cubic mm. how tall is the battery?

a. 56.3 mm
b. 16.5 mm
c. 18.6 mm
d. 59.3 mm

Explanation:

Step1: Recall the formula for the volume of a cylinder

The formula for the volume of a cylinder is \(V=\pi r^{2}h\), where \(V\) is the volume, \(r\) is the radius, and \(h\) is the height.

Step2: Substitute the given values into the formula

We know that \(V = 15908.5\) cubic mm and \(r=16.5\) mm. First, calculate \(r^{2}=(16.5)^{2}=272.25\). Then, substitute into the formula: \(15908.5=\pi\times272.25\times h\).

Step3: Solve for \(h\)

Since \(\pi\approx3.14\), we have \(15908.5 = 3.14\times272.25\times h\). First, calculate \(3.14\times272.25 = 854.865\). Then, \(h=\frac{15908.5}{854.865}\approx18.6\) mm.

Answer:

C. \(18.6\) mm