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choose the correct answer. a cyclist rides 5 miles in 20 minutes. \\(\\…

Question

choose the correct answer.
a cyclist rides 5 miles in 20 minutes.
\\(\frac{5\text{ mi}}{20\text{ min}}\\)
which graph describes this ratio?
hint: use the unit rate!

Explanation:

Step1: Calculate unit rate

The cyclist rides 5 miles in 20 minutes. The unit rate (miles per minute) is $\frac{5}{20} = 0.25$ mi/min. So, for every minute, the distance increases by 0.25 miles.

Step2: Analyze graphs

  • First graph: At 2 minutes, distance should be $2\times0.25 = 0.5$? Wait, no, wait. Wait, 5 miles in 20 minutes, so 1 mile in 4 minutes (since $20\div5 = 4$). So unit rate is 1 mile per 4 minutes (or 0.25 mi per min). Let's check time vs distance. For 4 minutes, distance is 1 mile; 8 minutes, 2 miles; 12 minutes, 3 miles? Wait no, original ratio is 5 mi in 20 min, so simplified, 1 mi in 4 min. So the graph should have a point at (4,1), (8,2), etc. Wait, let's check the x - axis (time) and y - axis (distance).
  • First graph: Let's see the x - axis labels. If time is in minutes, and at x = 2, y = 1? No, wait the first graph: when time is 2 min, distance is 1? But 2 min should be 0.5 mi (since 0.25*2 = 0.5). Wait, maybe I messed up. Wait the ratio is 5 mi / 20 min = 1 mi / 4 min. So the slope (unit rate) is 1/4 mi per min. So the equation is $y=\frac{1}{4}x$, where y is distance (mi) and x is time (min).
  • Let's check the three graphs:
  • First graph: Let's see the points. If x = 4, y should be 1. Let's check the first graph's grid. If the x - axis is time (min) with ticks at 1,2,3,4,5,6 and y - axis distance (mi) with ticks at 1,2,3,4,5,6. Wait, the first graph: when x = 2, y = 1; x = 4, y = 2; x = 6, y = 3. But according to our rate, x = 4 should be y = 1. So that's not right. Wait, maybe I got the axes reversed? No, y is distance, x is time.
  • Wait, maybe the first graph has a slope of 1/2? No. Wait, let's recalculate the unit rate correctly. 5 miles in 20 minutes. So per minute: 5/20 = 0.25 miles per minute. So in 4 minutes, 1 mile; 8 minutes, 2 miles; 12 minutes, 3 miles? No, 0.254 = 1, 0.258 = 2, 0.25*12 = 3. Wait, but 5 miles in 20 minutes, so 20 minutes is x = 20, y = 5. Let's check the graphs:
  • First graph: Let's see the x - axis (time) and y - axis (distance). If the first graph has a point at (2,1), (4,2), (6,3), that would be a slope of 0.5, which is not our rate.
  • Second graph: Let's see, when x = 4, y = 1; x = 8, y = 2. Wait, no, the second graph's points: if at x = 5, y = 1? No, wait the hint says use unit rate. Wait, maybe the first graph is wrong, the second? Wait, no, let's do it again. The ratio is 5 mi / 20 min = 1 mi / 4 min. So the graph should pass through (4,1), (8,2), (12,3), etc. Let's check the three graphs:
  • First graph: The line goes through (2,1), (4,2), (6,3). Slope is (2 - 1)/(4 - 2)= 0.5, which is 1/2, not 1/4.
  • Second graph: Let's see, when x = 5, y = 1? No, wait the second graph's x - axis: time (min) with ticks 1,2,3,4,5,6. y - axis: distance (mi) with ticks 1,2,3,4,5,6. Wait, the second graph's line: at x = 5, y = 1? No, that would be 1/5. No. Wait, maybe I made a mistake. Wait the original ratio is 5 mi in 20 min, so the unit rate is 5/20 = 0.25 mi per minute. So in 2 minutes, distance is 0.5 mi; 4 minutes, 1 mi; 6 minutes, 1.5 mi; 8 minutes, 2 mi. Wait, now looking at the first graph: when x = 2, y = 1 (which is 0.52), x = 4, y = 2 (0.54), x = 6, y = 3 (0.56). But our unit rate is 0.25, so that's double. Wait, maybe the first graph is incorrect. Wait the second graph: let's see, at x = 4, y = 1 (0.254 = 1), x = 8, y = 2 (0.258 = 2). Wait, no, the second graph's x - axis: if x = 4, y = 1; x = 8, y = 2. But the first graph: x = 2, y = 1 (0.52), which is 1 mi in 2 min, but we need 1 mi in 4 min. Wait, maybe the third graph? No, wait the fir…

Answer:

The Middle Graph