Question

a certain committee is composed of 11 juniors and 79 seniors. two different members of the committee will be randomly selected, each for a di given that the 1st member selected is a junior, what is the probability that the 2nd member selected will be a senior?
a. \\( \frac { 10 } { 79 } \\)
b. \\( \frac { 10 } { 89 } \\)
c. \\( \frac { 79 } { 89 } \\)
d. \\( \frac { 79 } { 90 } \\)

Explanation:

Step1: Calculate the total number of members after first selection

Total members initially = \(11 + 79=90\). After selecting 1 junior (1st member), the total number of remaining members is \(90 - 1=89\).

Step2: Calculate the number of seniors remaining

Number of seniors remains 79 (since 1st - selected member is a junior).

Step3: Calculate the probability

Probability \(P=\frac{\text{Number of seniors}}{\text{Total remaining members}}=\frac{79}{89}\)

Answer:

C. \(\frac{79}{89}\)