Question

the center of circle c is at (6,2), with a radius of 5. in order to prove that point d(6,-3) lies on the circle, what does the length of segment \\( \overline{cd} \\) need to be? hint: use distance formula (1 point) segment \\( \overline{cd} \\) must have a length of

Explanation:

Step1: Identify coordinates of C and D

Center \( C(6,2) \), point \( D(6,-3) \)

Step2: Apply distance formula

Distance \( CD = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{(6-6)^2 + (-3-2)^2} = \sqrt{0 + (-5)^2} = \sqrt{25} = 5 \)

Answer:

5