Question

1. cassidy had 8\frac{7}{16} inches of string. she used 5\frac{1}{8} inches of string. estimate the amount of string cassidy has left. \

ewline \textcircled{a} 2 inches \
ewline \textcircled{c} 3 inches \
ewline \textcircled{b} 4 inches \
ewline \textcircled{d} 5 inches

Explanation:

Step1: Round the mixed numbers

Round \( 8\frac{7}{16} \) to the nearest whole number. Since \( \frac{7}{16} \approx 0.4375 \), \( 8\frac{7}{16} \approx 8 \).
Round \( 5\frac{1}{8} \) to the nearest whole number. Since \( \frac{1}{8} = 0.125 \), \( 5\frac{1}{8} \approx 5 \).

Step2: Subtract the rounded values

To find the estimated remaining string, subtract the rounded used length from the rounded total length: \( 8 - 5 = 3 \). Wait, but let's check the fractions again. Wait, \( 8\frac{7}{16} \) is closer to 8, but maybe a better estimate: \( 8\frac{7}{16} \approx 8.5 \) (since \( \frac{7}{16} \) is more than half? Wait no, \( \frac{8}{16} = 0.5 \), so \( \frac{7}{16} \) is less than 0.5, so \( 8\frac{7}{16} \approx 8 \). \( 5\frac{1}{8} \): \( \frac{1}{8} = 0.125 \), so \( 5\frac{1}{8} \approx 5 \). But wait, maybe the problem expects rounding to the nearest whole number or to a simpler fraction. Wait, another way: \( 8\frac{7}{16} \) is about 8.44, \( 5\frac{1}{8} \) is about 5.125. Subtracting: \( 8.44 - 5.125 \approx 3.315 \), which is closest to 3. Wait, but the options include 3. Wait, maybe I made a mistake in rounding. Wait, \( 8\frac{7}{16} \): \( \frac{7}{16} \) is 0.4375, so 8.4375. \( 5\frac{1}{8} \) is 5.125. 8.4375 - 5.125 = 3.3125, which is approximately 3. So the estimated amount left is 3 inches.

Answer:

C. 3 inches