Question

a car goes from 37 km/hr to a complete stop in 14 seconds. what is the acceleration? answer: check what are the units for your answer to question 11? select one: km/hr/s, kilometers, seconds, km/hr

Explanation:

Step1: Recall acceleration formula

Acceleration \( a = \frac{\Delta v}{\Delta t} \), where \( \Delta v \) is change in velocity, \( \Delta t \) is time. Initial velocity \( v_i = 37 \, \text{km/hr} \), final velocity \( v_f = 0 \, \text{km/hr} \), \( \Delta t = 14 \, \text{s} \). So \( \Delta v = 0 - 37 = -37 \, \text{km/hr} \).

Step2: Calculate acceleration

\( a = \frac{-37 \, \text{km/hr}}{14 \, \text{s}} \approx -2.64 \, \text{km/hr/s} \) (negative for deceleration).

Answer:

\(-2.64 \, \text{km/hr/s}\) (or approximately \(-2.6 \, \text{km/hr/s}\), depending on rounding)