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calculating a rate of change of a quadratic function over an interval w…

Question

calculating a rate of change of a quadratic function over an interval which is the rate of change for the interval between 2 and 6 on the x-axis?
-3
-\frac{1}{3}
\frac{1}{3}
3

Explanation:

Step1: Find the coordinates at x=2 and x=6

From the graph, when \( x = 2 \), the corresponding \( y \)-value (let's call it \( y_1 \)) is 2 (by looking at the point on the parabola at \( x = 2 \)). When \( x = 6 \), the corresponding \( y \)-value (let's call it \( y_2 \)) is 14 (by looking at the point on the parabola at \( x = 6 \)). Wait, actually, maybe I misread. Wait, let's check the grid. Wait, the vertex is around x=1, y=1? Wait, no, let's re - examine. Wait, the standard formula for rate of change (slope) between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \( \text{Rate of change}=\frac{y_2 - y_1}{x_2 - x_1} \).

Looking at the graph, when \( x = 2 \), the point is (2, 2) (assuming the grid: each square is 1 unit). When \( x = 6 \), the point is (6, 14)? Wait, no, maybe I made a mistake. Wait, let's look again. Wait, the parabola: at[SSE Completed, Client Connection Error][SSE Completed, Client Connection Error][LLM SSE On Failure]

Answer:

3