Question

calculating acceleration

of washers initial velocity $v_1$ (m/s) final velocity $v_2$ (m/s) time to travel 0.25 m $t_1$ (s) time to travel 0.50 m $t_2$ (s) acceleration $a=(v_2 - v_1)/(t_2 - t_1)$ (m/s²)

1 0.11 0.28 2.23 3.13 0.19
2 0.13 0.36 1.92 2.61
the acceleration of the car with two washers added to the string would be

Explanation:

Step1: Identify values for 2 - washers case

$v_1 = 0.13$ m/s, $v_2=0.36$ m/s, $t_1 = 1.92$ s, $t_2 = 2.61$ s

Step2: Apply acceleration formula

$a=\frac{v_2 - v_1}{t_2 - t_1}=\frac{0.36 - 0.13}{2.61 - 1.92}$
$=\frac{0.23}{0.69}$
$= 0.33$ m/s²

Answer:

$0.33$ m/s²