Question

to calculate molarity, you have to divide
a small molarity means the solution is
a large molarity means the solution is
listed
mo
solution
dilute
weak
concentrated
in

Explanation:

The problem is about calculating molarity, which involves dividing moles of solute by liters of solution. For a small molarity, the solution (liters) would be larger or the moles smaller; for a large molarity, the solution (liters) would be smaller or the moles larger. The word bank has "moles", "solution", "dilute", "volume", "concentrated", etc. The first blank (to calculate molarity, divide [moles] by [volume/liters of solution]). The second: small molarity means solution is [large] (or moles small), third: large molarity means solution is [small] (or moles large). But from the word bank, likely: first blank "moles", second "liters" (but word bank has "solution"? Wait, the word bank on the left: "Liters", "moles", "solution", "dilute", "volume", "concentrated", "solute". So:

To calculate molarity, you have to divide moles by liters (but "Liters" is an option, or "volume"? Wait, molarity formula is \( M = \frac{n}{V} \), where \( n \) is moles, \( V \) is volume in liters. So first blank: moles, second: liters (or volume). Then "A small molarity means the solution is dilute" (since dilute has lower concentration, small M), "A large molarity means the solution is concentrated" (high concentration, large M). Wait, but the options: left word bank: Liters, moles, solution, dilute, volume, concentrated, solute.

So:

1. To calculate molarity, divide moles (of solute) by Liters (of solution, volume).

1. A small molarity means the solution is dilute (lower concentration).

1. A large molarity means the solution is concentrated (higher concentration).

Answer:

First blank: moles
Second blank: Liters
Third blank: dilute
Fourth blank: concentrated

(Assuming the blanks are: first "to calculate molarity, divide [moles] by [Liters]"; second "A small molarity means the solution is [dilute]"; third "A large molarity means the solution is [concentrated]")