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Question
brooks, nathaniel sy 25 26 ees unit 1 astronomy a student is analyzing the orbital path of a planet around the sun using the figure provided. the figure below shows 3 shaded areas (a to b, c to d, and e to f). based on your understanding of keplers laws, which conclusion about the time intervals is best supported by the data? the time interval from a to b is twice the interval from e to f, indicating that the planet moves more slowly near a to b due to being farther from the sun. the time intervals from a to b, c to d, and e to f are all equal because equal areas indicate that the planet takes the same amount of time to sweep each segment the time intervals from a to b, c to d, and e to f combine to be equal to one - half of a full orbit, reflecting the planets overall motion around the sun. the time intervals from a to b, c to d, and e to f combine to be equal to one - half of a full orbit, which shows the variation in the planets speed depending on its position in the orbit. the time intervals from c to d and from e to f combine to be equal to the time interval from a to b, which shows the variation in the planets speed depending on its position in the orbit.
Step1: Recall Kepler's second law
Kepler's second - law (law of equal areas) states that a line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time.
Step2: Analyze the shaded areas
The three shaded areas (A to B, C to D, and E to F) are equal in area. According to Kepler's second law, this means the time intervals for the planet to move from A to B, from C to D, and from E to F are equal.
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The time intervals from A to B, C to D, and E to F are all equal because equal areas indicate that the planet takes the same amount of time to sweep each segment.