Question

if a box weighing 520 n is hung from a spring whose constant is 650 n/m, how many centimeters will the spring stretch?
□ cm

Explanation:

Step1: Recall Hooke's Law

Hooke's Law states that the force \( F \) exerted by a spring is \( F = kx \), where \( k \) is the spring constant and \( x \) is the displacement (stretch or compression) of the spring. We need to solve for \( x \), so we rearrange the formula to \( x=\frac{F}{k} \).

Step2: Substitute the given values

We know that \( F = 520\space N \) and \( k = 650\space N/m \). Substituting these into the formula, we get \( x=\frac{520}{650}\space m \).

Step3: Calculate the value in meters

Simplifying \( \frac{520}{650} \), we divide numerator and denominator by 130: \( \frac{520\div130}{650\div130}=\frac{4}{5} = 0.8\space m \).

Step4: Convert meters to centimeters

Since \( 1\space m = 100\space cm \), we multiply the length in meters by 100: \( 0.8\space m\times100 = 80\space cm \).

Answer:

80