Question

a box contains ten cards labeled q, r, s, t, u, v, w, x, y, and z. one card will be randomly chosen. what is the probability of choosing a letter from u to z? write your answer as a fraction in simplest form.

Explanation:

Step1: Determine the number of favorable outcomes

The letters from \(U\) to \(Z\) are \(U, V, W, X, Y, Z\). So the number of favorable outcomes \(n(F)=6\).

Step2: Determine the total number of outcomes

There are \(10\) cards in total. So the total number of outcomes \(n(T) = 10\).

Step3: Calculate the probability

The probability formula is \(P=\frac{n(F)}{n(T)}\). Substituting the values, we get \(P=\frac{6}{10}\). Simplifying the fraction by dividing numerator and denominator by \(2\), we have \(P=\frac{3}{5}\).

Answer:

\(\frac{3}{5}\)