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4. $overrightarrow{kj}$ bisects $angle{okp}$. find the $mangle{okj}$ if…

Question

  1. $overrightarrow{kj}$ bisects $angle{okp}$. find the $mangle{okj}$ if the $mangle{okp}=71^{circ}$.

Explanation:

Step1: Recall angle - bisector definition

An angle - bisector divides an angle into two equal parts.

Step2: Calculate m∠OKJ

Since $\overrightarrow{KJ}$ bisects $\angle{OKP}$, then $m\angle{OKJ}=\frac{1}{2}m\angle{OKP}$. Given $m\angle{OKP} = 71^{\circ}$, so $m\angle{OKJ}=\frac{71^{\circ}}{2}=35.5^{\circ}$.

Answer:

$35.5^{\circ}$