Question

betty runs a day care center. of the 18 children at the day care center, 4 of them are seven - year - olds.
what is the probability that a randomly selected child will be a seven - year - old?
write your answer as a fraction or whole number.
p(seven - year - old) =

Explanation:

Step1: Recall probability formula

Probability \( P(A)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \)
Here, the number of favorable outcomes (seven - year - olds) is \( 4 \), and the total number of outcomes (total children) is \( 18 \).
So, \( P(\text{seven - year - old})=\frac{4}{18} \)

Step2: Simplify the fraction

Divide numerator and denominator by their greatest common divisor. The GCD of \( 4 \) and \( 18 \) is \( 2 \).
\( \frac{4\div2}{18\div2}=\frac{2}{9} \)

Answer:

\(\frac{2}{9}\)