Question

beth anne marks the points (6,1) and (-9,6) on the coordinate plane. what is the distance between those points, rounded to the nearest tenth of a unit? (1 point) 20.0 units 15.8 units 10.0 units 16.2 units

Explanation:

Step1: Identify the coordinates

Let \((x_1,y_1)=(6,1)\) and \((x_2,y_2)=(-9,6)\)

Step2: Use the distance formula

The distance formula is \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\)
Substitute the values: \(d=\sqrt{(-9 - 6)^2+(6 - 1)^2}\)

Step3: Calculate the differences

\(-9-6=-15\) and \(6 - 1 = 5\)
So \(d=\sqrt{(-15)^2+5^2}=\sqrt{225 + 25}\)

Step4: Simplify the expression

\(d=\sqrt{250}\approx15.8\)

Answer:

15.8 units