Question

on below. what’s the value of c?
= -2c + 4
= -2c + 4
+ 2c
2 =

Explanation:

Step1: Assume the left side is 2c + 2 (from the left box 2, maybe a typo or missing part, let's correct the equation. Let's assume the original equation is \(2c + 2=-2c + 4\))

First, add \(2c\) to both sides: \(2c + 2+2c=-2c + 4+2c\)
Simplify: \(4c + 2 = 4\)

Step2: Subtract 2 from both sides: \(4c+2 - 2=4 - 2\)

Simplify: \(4c = 2\)

Step3: Divide both sides by 4: \(c=\frac{2}{4}\)

Simplify: \(c=\frac{1}{2}\) Wait, maybe the left side is 2 (from the box 2). Let's re - evaluate. If the equation is \(2=-2c + 4\)

Step1: Subtract 4 from both sides: \(2-4=-2c + 4-4\)

Simplify: \(-2=-2c\)

Step2: Divide both sides by - 2: \(c = 1\)

Wait, the operation shown is adding \(2c\) to both sides. Let's do it as per the operation. Let the left side be \(2\) (from the box 2). So:

Step1: Start with \(2=-2c + 4\)

Add \(2c\) to both sides: \(2 + 2c=-2c+4 + 2c\)
Simplify: \(2 + 2c=4\)

Step2: Subtract 2 from both sides: \(2c+2 - 2=4 - 2\)

Simplify: \(2c = 2\)

Step3: Divide both sides by 2: \(c = 1\)

Answer:

\(c = 1\)