Question

bd bisects ∠abc; the m∠abc = 122°. find m∠abd and m∠dbc. m∠abd = m∠dbc =

Explanation:

Step1: Recall angle - bisector definition

A bisector of an angle divides the angle into two equal parts. If $\overrightarrow{BD}$ bisects $\angle ABC$, then $\angle ABD=\angle DBC$.

Step2: Calculate the measure of the sub - angles

Given $m\angle ABC = 122^{\circ}$, and since $\angle ABD=\angle DBC=\frac{1}{2}m\angle ABC$, we have $\angle ABD=\angle DBC=\frac{122^{\circ}}{2}=61^{\circ}$.

Answer:

$m\angle ABD = 61^{\circ}$
$m\angle DBC = 61^{\circ}$