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basketball regression line prediction: suppose the equation for the reg…

Question

basketball regression line prediction: suppose the equation for the regression line for the number of games won in a season, y, is given by: y = 102 - 0.053x where x is number of turnovers by the team in a season. for a team with 1097 turnovers in a season, find the expected number of wins in a season. round your answer to the nearest whole number. question help: post to forum submit question jump to answer

Explanation:

Step1: Substitute the value of \(x\) into the regression equation

Given \(x = 1097\) and \(y=102 - 0.053x\), substitute \(x\) into the equation:
\(y=102-0.053\times1097\)

Step2: Calculate the product

First, calculate \(0.053\times1097\):
\(0.053\times1097 = 58.141\)

Step3: Calculate the value of \(y\)

Then, calculate \(y = 102-58.141\):
\(y=43.859\)

Step4: Round to the nearest whole number

Round \(43.859\) to the nearest whole number. Since the decimal part \(0.859>0.5\), we round up.
\(y\approx44\)

Answer:

\(44\)