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the base of the right triangle drawn in the regular octagon measures 0.…

Question

the base of the right triangle drawn in the regular octagon measures 0.7 cm.
what is the perimeter of the octagon?
○ 11.2 cm
○ 14.1 cm
○ 15.2 cm
○ 20.8 cm

Explanation:

Step1: Recall the property of a regular octagon

A regular octagon has 8 equal - length sides. The right - triangle drawn from the center of the octagon to a side is such that the base of the right - triangle (\(0.7\) cm) is half of the side - length of the octagon.

Step2: Calculate the side - length of the octagon

Let \(s\) be the side - length of the octagon. Then \(s = 2\times0.7=1.4\) cm.

Step3: Calculate the perimeter of the octagon

The formula for the perimeter \(P\) of a regular polygon is \(P = n\times s\), where \(n\) is the number of sides and \(s\) is the side - length. For an octagon, \(n = 8\) and \(s = 1.4\) cm. So \(P=8\times1.4\).

$$P = 11.2$$

Answer:

11.2 cm