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a ball is thrown straight upward. a position function ( s(t)=\frac{1}{2…

Question

a ball is thrown straight upward. a position function ( s(t)=\frac{1}{2} g t^{2}+v_{0} t+s_{0} ) can be used to describe the balls height, ( s(t) ), in feet, after ( t ) seconds. a graph of the balls height is shown to the right. complete parts a through c below. (simplify your answer.) interpret ( s(3.25) ). choose the correct answer below a. the ball hits the ground 3.25 seconds after it is thrown b. the ball is below ground 3.25 seconds after it is thrown c. the ball is half its highest height 3.25 seconds after it is thrown d. the ball hits its highest height 3.25 seconds after it is thrown c. after how many seconds does the ball reach its maximum height? what is its maximum height? the ball reaches its maximum height after ( square ) seconds (type an integer or a decimal)

Explanation:

Step1: Identify the maximum point on the graph

The maximum height of the ball occurs at the vertex of the parabola. Looking at the graph, the vertex is at the point \((2,40)\).

Answer:

The ball reaches its maximum height after \(2\) seconds.