Question

bag a has 2 yellow marbles, 4 red marbles, and 2 blue marbles. bag b has 6 yellow marbles, 1 red marble, and 1 blue marble. bag c has 8 yellow marbles. picking a yellow marble from bag a is ______. certain likely unlikely impossible picking a yellow marble from bag b is ____. certain likely unlikely impossible picking a yellow marble from bag c is ______. certain likely unlikely impossible

Explanation:

Bag A

Step1: Calculate total marbles

Total marbles in Bag A: \(2 + 4+2=8\)

Step2: Calculate probability of yellow marble

Probability of picking yellow: \(\frac{2}{8}=\frac{1}{4}\). Since \(\frac{1}{4}<\frac{1}{2}\), it is unlikely.

Bag B

Step1: Calculate total marbles

Total marbles in Bag B: \(6 + 1+1=8\)

Step2: Calculate probability of yellow marble

Probability of picking yellow: \(\frac{6}{8}=\frac{3}{4}\). Since \(\frac{3}{4}>\frac{1}{2}\), it is likely.

Bag C

Step1: Check marble composition

Bag C has only yellow marbles. So probability of picking yellow is \(1\) (certain).

Answer:

Bag A: unlikely, Bag B: likely, Bag C: certain