Question

the axis of symmetry for $p(x)=2x^{2}-8x + 11$ is $x=$

Explanation:

Step1: Recall axis - of - symmetry formula

For a quadratic function $y = ax^{2}+bx + c$, the axis of symmetry is given by $x=-\frac{b}{2a}$.

Step2: Identify a and b values

In the function $p(x)=2x^{2}-8x + 11$, $a = 2$ and $b=-8$.

Step3: Calculate the axis of symmetry

Substitute $a = 2$ and $b=-8$ into the formula $x=-\frac{b}{2a}$. We get $x=-\frac{-8}{2\times2}=\frac{8}{4}=2$.

Answer:

$2$