Question

$x^2 + 5x - 50$
attempt 1 out of 2

Explanation:

Step1: Find two numbers

We need two numbers that multiply to $-50$ and add up to $5$. Let's list the factor pairs of $-50$: $(-5, 10)$ since $-5\times10 = -50$ and $-5 + 10 = 5$.

Step2: Factor the quadratic

Using the numbers from Step 1, we can factor $x^2 + 5x - 50$ as $(x - 5)(x + 10)$ because when we expand $(x - 5)(x + 10)$ using the distributive property (FOIL method), we get $x^2 + 10x - 5x - 50 = x^2 + 5x - 50$, which matches the original quadratic.

Answer:

$(x - 5)(x + 10)$