Question

assume the hold time of callers to a cable company is normally distributed with a mean of 3.9 minutes and a standard deviation of 0.9 minute. determine the percent of callers who are on hold for more than 3.9 minutes.

click here to view page 1 of the standard normal distribution table.
click here to view page 2 of the standard normal distribution table.

\\(\square\\)% (round to two decimal places as needed.)

Explanation:

Identify the given parameters and target probability

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Calculate the Z-score for the boundary value

$$ Z = \frac{X - \mu}{\sigma} = \frac{3.9 - 3.9}{0.9} = 0 $$

Determine the percentage using normal distribution symmetry

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Answer:

Assume the hold time of callers to a cable company is normally distributed with a mean of 3.9 minutes and a standard deviation of 0.9 minute. Determine the percent of callers who are on hold for more than 3.9 minutes.

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